Source: Exemplar
In triangles ABC and DEF, AB = FD and ∠A = ∠D. The two triangles will be congruent by SAS axiom if
Options
Option A
BC = EF
Option B is correct
AC = DE
Option C
AC = EF
Option D
BC = DE
In triangles ABC and DEF, AB = FD and ∠A = ∠D. The two triangles will be congruent by SAS axiom if
BC = EF
AC = DE
AC = EF
BC = DE