Source: Exemplar
D and E are the mid-points of the sides AB and AC respectively of ∆ABC. DE is produced to F. To prove that CF is equal and parallel to DA, we need an additional information which is
Options
Option A
∠DAE = ∠EFC
Option B
AE = EF
Option C is correct
DE = EF
Option D
∠ADE = ∠ECF