In the reaction N2(g) + 3H2(g) → 2NH3(g), if 2.0 moles of N2 react with 3.0 moles of H2, which is the limiting reagent?

Model Answer & Options

Source: Extra Practice

N2

H2

NH3

None of these

Explanation

According to the balanced equation, 1 mole of N2 requires 3 moles of H2. For 2.0 moles of N2, we need 2 × 3 = 6.0 moles of H2. Since we only have 3.0 moles of H2, H2 will be consumed first and is the limiting reagent. N2 is in excess. NH3 is a product, not a reagent.

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