To solve a definite integral, first find the indefinite integral: ∫(6x² + 2) dx = 6(x³/3) + 2x = 2x³ + 2x. Next, apply the Fundamental Theorem of Calculus by substituting the upper limit (2) and subtracting the result of substituting the lower limit (1). For x=2: 2(2)³ + 2(2) = 16 + 4 = 20. For x=1: 2(1)³ + 2(1) = 2 + 2 = 4. The final value is 20 - 4 = 16. Option 2 is just the upper limit value, and options 3 and 4 result from calculation errors in integration or subtraction.