The value of 7^{log_7 5} + 2^{log_2 3} is equal to:

Model Answer & Options

Source: Extra Practice

8

15

10

35

Explanation

The fundamental property of logarithms states that a^{log_a n} = n. Applying this to both terms: 7^{log_7 5} = 5 and 2^{log_2 3} = 3. Adding them gives 5 + 3 = 8. The other options result from incorrectly multiplying the numbers or ignoring the log properties.

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