Calculating the value: $X = \frac{(2.0)^2 \times 3.00}{(1.000)^3} = \frac{4.0 \times 3.00}{1.000} = 12$. For multiplication and division, the result must possess the same number of significant figures as the term with the fewest significant figures. The component 'a' ($2.0$) has 2 significant figures, 'b' ($3.00$) has 3, and 'c' ($1.000$) has 4. Therefore, the result must have exactly 2 significant figures, which is represented by $12$.