Source: Exemplar

If && is an operation such that for integers a and b we have a && b = a × a + b × b – a × b, then find (–3) && 2.

Model Answer

Given a && b=a2+b2aba \ \&\& \ b = a^2 + b^2 - ab. For a=3a = -3 and b=2b = 2, we get: (3) && 2=(3)2+22(3)(2)=9+4+6=19(-3) \ \&\& \ 2 = (-3)^2 + 2^2 - (-3)(2) = 9 + 4 + 6 = 19.