Source: Previous Question Papers

Find the additive inverse of the product of multiplicative inverse of 7691\frac{76}{91} and multiplicative inverse of 6557\frac{65}{57}

Options

Option A

+2120+\frac{21}{20}

Option B is correct

2120-\frac{21}{20}

Option C

+2021+\frac{20}{21}

Option D

2021-\frac{20}{21}

Explanation

The multiplicative inverse of 7691\frac{76}{91} is 9176\frac{91}{76}. The multiplicative inverse of 6557\frac{65}{57} is 5765\frac{57}{65}. The product of these inverses is P=9176×5765P = \frac{91}{76} \times \frac{57}{65}. We can simplify this expression: P=7×134×19×3×195×13P = \frac{7 \times 13}{4 \times 19} \times \frac{3 \times 19}{5 \times 13}. Cancelling out common factors (1313 and 1919), we get P=7×34×5=2120P = \frac{7 \times 3}{4 \times 5} = \frac{21}{20}. The additive inverse of PP is P=2120-P = -\frac{21}{20}.