Let the given expression be E=31×32×30×33+1. We can rearrange the terms as E=30×31×32×33+1.
Let x=30. Then the expression becomes E=x(x+1)(x+2)(x+3)+1.
We can group the terms: E=[x(x+3)][(x+1)(x+2)]+1.
This simplifies to E=(x2+3x)(x2+3x+2)+1.
Let y=x2+3x. Substituting y into the expression, we get:
E=y(y+2)+1E=y2+2y+1E=(y+1)2E=∣y+1∣
Since x=30, y=302+3(30)=900+90=990.
Therefore, E=∣990+1∣=991.
Thus, the value of the expression is 991.