A person lifts a 2 kg block from the ground to a height of 5 meters. Calculate the work done by the person against gravity. (Assume g=10 m/s2g = 10 \ m/s^2)

Options

Option A

0 J

Option B

10 J

Option C is correct

100 J

Option D

200 J

Explanation

The work done by the person against gravity is equal to the potential energy gained by the block. The formula for potential energy is PE=mghPE = mgh, where mm is the mass, gg is the acceleration due to gravity, and hh is the height. Given: Mass (mm) = 2 kg Height (hh) = 5 m Acceleration due to gravity (gg) = 10 m/s210 \ m/s^2 Work done (WW) = PE=mgh=2×10×5=100 JPE = mgh = 2 \times 10 \times 5 = 100 \ J. Therefore, the work done by the person against gravity is 100 J. Options A, B, and D are incorrect as they do not match the calculated work done.