Questions & Answers: "Volume and Surface Area"

Complete guide to "Volume and Surface Area" for Math students. Below you will find important questions and model answers to help you prepare.

4 Questions

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We are building a dedicated quiz for this topic, but you can test your skills on a similar concept: Geometry (Angles, Circles, and 3D Nets) - Scholarship-VIII Practice Set 1.

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Question 1

1 Mark

In a cuboid shape tank, water is being poured from the tap at the rate of 60 l/min. The capacity of the tank is 108 cu.m. How much time will be required to fill the tank to half of its capacity?

Options

Option A

10 hrs.

Option B

3 hrs.

Option C

30 hrs.

Option D is correct

15 hrs.

Question 2

1 Mark

Find the capacity of a cubical tank having each side 1.5 m. (Select two correct alternative.)

Options

Option A is correct

3375 lit

Option B

4375 lit

Option C is correct

3.375 cubic m

Option D

4.375 cubic m

Question 3

1 Mark

Find the capacity of a cylindrical cement tank of water, if the diameter of the tank is 7m and height is 2m. (Select two correct alternatives.)

Options

Option A

88 cubic m

Option B is correct

77 cubic m

Option C

88000 litres

Option D is correct

77000 litres

Explanation

The diameter of the cylindrical tank is 77m, so the radius r=72r = \frac{7}{2}m. The height h=2h = 2m. The volume (capacity) of the cylinder is given by V=πr2hV = \pi r^2 h. Substituting the values, V=227×(72)2×2=227×494×2=22×7×24=11×7×22=77V = \frac{22}{7} \times (\frac{7}{2})^2 \times 2 = \frac{22}{7} \times \frac{49}{4} \times 2 = \frac{22 \times 7 \times 2}{4} = \frac{11 \times 7 \times 2}{2} = 77 cubic m. Since 11 cubic m =1000= 1000 litres, the capacity in litres is 77×1000=7700077 \times 1000 = 77000 litres.

Question 4

1 Mark

The radius of the base of a cone is 21 cm and its height is 20 cm. Find its volume.

Options

Option A

9204 cubic cm

Option B

9042 cubic cm

Option C is correct

9240 cubic cm

Option D

9273 cubic cm

Explanation

The formula for the volume of a cone (VV) is V=13πr2hV = \frac{1}{3} \pi r^2 h, where rr is the radius of the base and hh is the height. Given: Radius (rr) = 21 cm Height (hh) = 20 cm Using π=227\pi = \frac{22}{7}:V=13×227×(21 cm)2×20 cmV = \frac{1}{3} \times \frac{22}{7} \times (21\text{ cm})^2 \times 20\text{ cm} V=13×227×21×21×20V = \frac{1}{3} \times \frac{22}{7} \times 21 \times 21 \times 20 We can simplify the calculation: V=13×22×(217)×21×20V = \frac{1}{3} \times 22 \times \left(\frac{21}{7}\right) \times 21 \times 20 V=13×22×3×21×20V = \frac{1}{3} \times 22 \times 3 \times 21 \times 20Cancel out the 33 in the denominator and numerator:V=22×21×20V = 22 \times 21 \times 20First, calculate 22×2122 \times 21:22×21=46222 \times 21 = 462Now, multiply by 2020:V=462×20=9240V = 462 \times 20 = 9240Therefore, the volume of the cone is 92409240 cubic cm.