Solve for real x: (x / 4) < (5x - 2) / 3 - (7x - 3) / 5
Model Answer & Options
Source: Extra Practice(4, ∞)
(-∞, 4)
[4, ∞)
(-∞, 4]
Explanation
To solve the inequality (x / 4) < (5x - 2) / 3 - (7x - 3) / 5, first find the LCM of the denominators on the RHS (3 and 5), which is 15. Simplify the RHS: [5(5x - 2) - 3(7x - 3)] / 15 = (25x - 10 - 21x + 9) / 15 = (4x - 1) / 15. Now we have x / 4 < (4x - 1) / 15. Multiply both sides by 60 (the LCM of 4 and 15) to clear fractions: 15x 15x < 16x - 4. Subtracting 16x from both sides gives -x 4. In interval notation, this is (4, ∞). Option B is incorrect as it represents x < 4. Options C and D are incorrect because the original inequality was strict (<), meaning the endpoint 4 is not included.
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