The absolute value inequality |x - a| ≤ r is equivalent to a - r ≤ x ≤ a + r. Here, a = 1 and r = 2. So, 1 - 2 ≤ x ≤ 1 + 2, which gives -1 ≤ x ≤ 3. In interval notation, this is [-1, 3]. Option 1 is incorrect because it uses open intervals. Options 3 and 4 are incorrect due to calculation errors in applying the boundary values.