Correct Option: Using the property |X| ≤ a ⇔ -a ≤ X ≤ a, we get -4 ≤ 3x - 2 ≤ 4. Adding 2 to all parts gives -2 ≤ 3x ≤ 6. Dividing by 3 gives -2/3 ≤ x ≤ 2. In interval notation, this is [-2/3, 2]. Incorrect Options: Option 2 uses open intervals which is incorrect for ≤; Option 3 has an incorrect lower bound; Option 4 represents the solution for |3x - 2| ≥ 4.