The modulus function |x - 3| is always greater than or equal to 0 for all real x. Therefore, the minimum value of |x - 3| is 0 (at x = 3). Adding 2 to this result gives f(x) ≥ 0 + 2, which means f(x) ≥ 2. Thus, the range is [2, ∞). Option B is wrong because the value 2 is included. Option C is the range of |x-3| only. Option D is wrong because modulus functions cannot output negative values in this context.