The length and breadth of a rectangular sheet are 16.2±0.1 cm16.2 \pm 0.1\text{ cm} and 10.1±0.1 cm10.1 \pm 0.1\text{ cm} respectively. The area of the sheet in appropriate significant figures and error is:

Model Answer & Options

Source: Extra Practice

163.62 ± 2.6 cm²

163.6 ± 2.6 cm²

164 ± 3 cm²

163.6 ± 3 cm²

Explanation

Area A=l×b=16.2×10.1=163.62 cm2A = l \times b = 16.2 \times 10.1 = 163.62\text{ cm}^2. Relative error ΔAA=Δll+Δbb=0.116.2+0.110.10.00617+0.00990=0.01607\frac{\Delta A}{A} = \frac{\Delta l}{l} + \frac{\Delta b}{b} = \frac{0.1}{16.2} + \frac{0.1}{10.1} \approx 0.00617 + 0.00990 = 0.01607. Absolute error ΔA=A×0.01607=163.62×0.016072.63 cm2\Delta A = A \times 0.01607 = 163.62 \times 0.01607 \approx 2.63\text{ cm}^2. Since the least significant figure in the measurements is at the tenths place and the product must follow the least significant figures of the factors (3 sig figs here), we round 163.62 to 164. The error is rounded to 3 to match the precision. Thus, 164±3164 \pm 3 is the most appropriate representation according to NCERT guidelines for propagation and rounding.

Try a Related Quiz

Test your skills on a similar concept: Units and Measurement - NCERT Class 11 Practice Set 1.

Start Related Quiz

Explore the Full Topic

This is just one question from the topic "error analysis".

View All Questions

Related Questions