If the error in the measurement of the radius of a sphere is 2%, then the error in the determination of its volume will be:

Model Answer & Options

Source: Extra Practice

6%

2%

4%

8%

Explanation

Volume of a sphere V = (4/3)πr³. The relative error is ΔV/V = 3(Δr/r). Given Δr/r = 2%, the percentage error in volume is 3 × 2% = 6%. 2% is the error in radius, 4% would be the error in surface area (r²), and 8% is a calculation error.

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