Source: Extra Practice

What is the dimensional formula for the Universal Gravitational Constant (GG)?

Options

Option A is correct

[M1L3T2][M^{-1}L^3T^{-2}]

Option B

[ML3T2][ML^3T^{-2}]

Option C

[M2L2T2][M^{-2}L^2T^{-2}]

Option D

[ML1T2][ML^{-1}T^{-2}]

Explanation

According to Newton's law of universal gravitation, the force FF between two masses M1M_1 and M2M_2 separated by a distance rr is given by F=GM1M2r2F = \frac{GM_1M_2}{r^2}. Rearranging this equation for GG, we get G=Fr2M1M2G = \frac{Fr^2}{M_1M_2}. The dimensional formula for force FF is [MLT2][MLT^{-2}]. The dimension for distance rr is [L][L], so r2r^2 has dimensions [L2][L^2]. The dimension for mass MM is [M][M], so M1M2M_1M_2 has dimensions [M2][M^2]. Substituting these into the formula for GG: [G]=[MLT2][L2][M2]=[M12L1+2T2]=[M1L3T2][G] = \frac{[MLT^{-2}][L^2]}{[M^2]} = [M^{1-2}L^{1+2}T^{-2}] = [M^{-1}L^3T^{-2}].