Source: Extra Practice

A student measures the length of a rod as 12.412.4 cm and its width as 4.124.12 cm. What should be the area of the rod, reported with the correct number of significant figures?

Options

Option A

51.088 cm251.088 \text{ cm}^2

Option B

51.09 cm251.09 \text{ cm}^2

Option C is correct

51.1 cm251.1 \text{ cm}^2

Option D

51 cm251 \text{ cm}^2

Explanation

Given length L=12.4 cmL = 12.4 \text{ cm}. This measurement has 3 significant figures. Given width W=4.12 cmW = 4.12 \text{ cm}. This measurement also has 3 significant figures. The area is calculated by multiplying length and width: A=L×W=12.4 cm×4.12 cm=51.088 cm2A = L \times W = 12.4 \text{ cm} \times 4.12 \text{ cm} = 51.088 \text{ cm}^2 . When multiplying or dividing measurements, the final result should be rounded to the same number of significant figures as the measurement with the fewest significant figures. In this case, both measurements have 3 significant figures. Therefore, the area should be rounded to 3 significant figures. 51.08851.088 rounded to 3 significant figures is 51.151.1 (since the first dropped digit, 8, is greater than or equal to 5, the preceding digit is rounded up).