Source: Extra Practice

In the equation y=Asin(ωtkx)y = A \sin(\omega t - kx), where yy is displacement, tt is time, and xx is distance. What are the dimensions of the constant kk?

Options

Option A

[L][L]

Option B is correct

[L1][L^{-1}]

Option C

[T][T]

Option D

[T1][T^{-1}]

Explanation

For any trigonometric function, its argument must be dimensionless. Therefore, the quantity (ωtkx)(\omega t - kx) must be dimensionless ([M0L0T0][M^0L^0T^0]). This implies that both ωt\omega t and kxkx must individually be dimensionless. Considering the term kxkx: [kx]=[M0L0T0][kx] = [M^0L^0T^0] Since xx is distance, its dimension is [L][L]. So, [k][L]=[M0L0T0][k][L] = [M^0L^0T^0]. Therefore, [k]=[L1][k] = [L^{-1}]. (Here kk is the wave number).