Questions & Answers: "Arithmetic Expressions"

Complete guide to "Arithmetic Expressions" for Math students. Below you will find important questions and model answers to help you prepare.

20 Questions

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Question 1

1 Mark

Evaluate the expression: 18×520÷4+718 \times 5 - 20 \div 4 + 7.

Options

Option A is correct

92

Option B

78

Option C

7

Option D

80

Explanation

The correct option is 92. According to the order of operations (BODMAS/PEMDAS), we first perform multiplication and division from left to right, and then addition and subtraction from left to right.\n1. Perform multiplication: 18×5=9018 \times 5 = 90.\n2. Perform division: 20÷4=520 \div 4 = 5.\n3. The expression becomes: 905+790 - 5 + 7.\n4. Perform subtraction: 905=8590 - 5 = 85.\n5. Perform addition: 85+7=9285 + 7 = 92.\nIncorrect options arise from violating the order of operations, such as performing subtraction before division or multiplication.

Question 2

1 Mark

Calculate the value of 25[10+(15÷(3))]×225 - [10 + (15 \div (-3))] \times 2.

Options

Option A is correct

15

Option B

-5

Option C

5

Option D

25

Explanation

The correct option is 15. We follow the BODMAS/PEMDAS rule.\n1. Innermost parentheses: 15÷(3)=515 \div (-3) = -5.\n2. The expression inside the square bracket becomes: 10+(5)=105=510 + (-5) = 10 - 5 = 5.\n3. The expression now is: 25[5]×225 - [5] \times 2.\n4. Perform multiplication: 5×2=105 \times 2 = 10.\n5. Finally, perform subtraction: 2510=1525 - 10 = 15.\nIncorrect options result from errors in integer arithmetic (e.g., sign errors in division or addition) or incorrect application of the order of operations, such as performing subtraction or addition before multiplication.

Question 3

1 Mark

A submarine is at 250 m below sea level. It rises 75 m, then dives 120 m. What is its final depth?

Options

Option A is correct

-295 m

Option B

205 m

Option C

-55 m

Option D

295 m

Explanation

The correct option is -295 m.\n1. Represent the initial depth below sea level as a negative integer: -250 m.\n2. A rise of 75 m means adding 75: 250+75-250 + 75.\n3. A dive of 120 m means subtracting 120: 120-120.\n4. The arithmetic expression is: 250+75120-250 + 75 - 120.\n5. Evaluate the expression:\n 250+75=175-250 + 75 = -175.\n 175120=295-175 - 120 = -295.\nSo, the final depth is -295 m, meaning 295 m below sea level.\nIncorrect options arise from errors in representing 'below sea level' as a negative integer, or incorrect application of addition and subtraction rules for integers, especially when dealing with 'rise' and 'dive'.

Question 4

1 Mark

A student calculated the value of 306×2+430 - 6 \times 2 + 4 as 52. What is the correct value of the expression?

Options

Option A is correct

22

Option B

52

Option C

14

Option D

-6

Explanation

The correct option is 22.\nThe given expression is 306×2+430 - 6 \times 2 + 4. According to the BODMAS/PEMDAS rule, multiplication should be performed before addition or subtraction.\n1. Perform multiplication: 6×2=126 \times 2 = 12.\n2. The expression becomes: 3012+430 - 12 + 4.\n3. Now perform subtraction and addition from left to right: 3012=1830 - 12 = 18.\n4. Finally, perform addition: 18+4=2218 + 4 = 22.\nThe student's answer of 52 results from performing operations from left to right without respecting the order of operations (306=2430 - 6 = 24, then 24×2=4824 \times 2 = 48, then 48+4=5248 + 4 = 52). Option 14 would result from doing addition before subtraction (30(12+4)30 - (12+4)).

Question 5

1 Mark

Evaluate: 60÷[(3)×2(84)]+1060 \div [(-3) \times 2 - (8 - 4)] + 10.

Options

Option A is correct

4

Option B

16

Option C

0

Option D

-34

Explanation

The correct option is 4. We apply the BODMAS/PEMDAS rule.\n1. Innermost parentheses: (84)=4(8 - 4) = 4.\n2. Inside the square bracket, perform multiplication first: (3)×2=6(-3) \times 2 = -6.\n3. Complete the square bracket: [64]=10[-6 - 4] = -10.\n4. The expression becomes: 60÷[10]+1060 \div [-10] + 10.\n5. Perform division: 60÷(10)=660 \div (-10) = -6.\n6. Finally, perform addition: 6+10=4-6 + 10 = 4.\nIncorrect options arise from errors such as incorrect signs for integer operations (e.g., option 16 forgets the negative sign for 60÷(10)60 \div (-10)) or incorrect application of the order of operations (e.g., option -34 results from ignoring the brackets for division).

Question 6

1 Mark

Evaluate the arithmetic expression: 18÷3+5×2418 \div 3 + 5 \times 2 - 4.

Options

Option A

1010

Option B is correct

1212

Option C

1616

Option D

2020

Explanation

According to the order of operations (BODMAS/PEMDAS - Brackets, Orders, Division/Multiplication, Addition/Subtraction):

  1. Division: 18÷3=618 \div 3 = 6
  2. Multiplication: 5×2=105 \times 2 = 10 The expression becomes: 6+1046 + 10 - 4
  3. Addition: 6+10=166 + 10 = 16
  4. Subtraction: 164=1216 - 4 = 12 Thus, the correct value of the expression is 1212. Options A, C, and D are incorrect as they do not follow the proper order of operations.

Question 7

1 Mark

What is the value of the expression: (5)+12×(2)10÷5(-5) + 12 \times (-2) - 10 \div 5?

Options

Option A is correct

31-31

Option B

17-17

Option C

1919

Option D

3131

Explanation

Following the order of operations:

  1. Multiplication: 12×(2)=2412 \times (-2) = -24
  2. Division: 10÷5=210 \div 5 = 2 The expression transforms to: (5)+(24)2(-5) + (-24) - 2
  3. Now perform addition and subtraction from left to right: 524=29-5 - 24 = -29 292=31-29 - 2 = -31 Therefore, the correct value is 31-31. Options B, C, and D result from incorrect application of integer rules or order of operations.

Question 8

1 Mark

Simplify the expression: 5×[10(82×(64))]5 \times [10 - (8 - 2 \times (6 - 4))].

Options

Option A

1010

Option B

2020

Option C is correct

3030

Option D

4040

Explanation

We simplify the expression by working from the innermost brackets outwards:

  1. Innermost parenthesis: (64)=2(6 - 4) = 2 The expression becomes: 5×[10(82×2)]5 \times [10 - (8 - 2 \times 2)]
  2. Multiplication inside parenthesis: 2×2=42 \times 2 = 4 The expression becomes: 5×[10(84)]5 \times [10 - (8 - 4)]
  3. Subtraction inside parenthesis: (84)=4(8 - 4) = 4 The expression becomes: 5×[104]5 \times [10 - 4]
  4. Subtraction inside square bracket: [104]=6[10 - 4] = 6 The expression becomes: 5×65 \times 6
  5. Final Multiplication: 5×6=305 \times 6 = 30 Thus, the simplified value is 3030. Other options result from errors in the order of operations, especially with brackets.

Question 9

1 Mark

A bus started with 60 passengers. At the first stop, 15 passengers got off and 7 passengers got on. At the second stop, 10 passengers got off and 12 passengers got on. Which expression correctly calculates the final number of passengers and what is the result?

Options

Option A is correct

Expression: 6015+710+1260 - 15 + 7 - 10 + 12; Result: 5454

Option B

Expression: 60+15710+1260 + 15 - 7 - 10 + 12; Result: 7070

Option C

Expression: 60157+101260 - 15 - 7 + 10 - 12; Result: 3636

Option D

Expression: 60+15+7101260 + 15 + 7 - 10 - 12; Result: 6060

Explanation

Let's track the changes in the number of passengers:

  • Started with: 6060
  • At first stop: 15 got off (15-15), 7 got on (+7+7). Current passengers: 6015+760 - 15 + 7
  • At second stop: 10 got off (10-10), 12 got on (+12+12). Final passengers: 6015+710+1260 - 15 + 7 - 10 + 12 This matches the expression in option A. Now, let's calculate the result: 6015=4560 - 15 = 45 45+7=5245 + 7 = 52 5210=4252 - 10 = 42 42+12=5442 + 12 = 54 The final number of passengers is 5454. Therefore, option A is correct as both the expression and the result are accurate. The other options have incorrect expressions or incorrect calculations based on the given information.

Question 10

1 Mark

Which of the following statements is true?

Options

Option A

205×2=3020 - 5 \times 2 = 30

Option B is correct

15÷3+4=915 \div 3 + 4 = 9

Option C

10+8÷2=910 + 8 \div 2 = 9

Option D

2×(5+3)=132 \times (5 + 3) = 13

Explanation

Let's evaluate each option using the order of operations:

  • Option A: 205×220 - 5 \times 2 Multiplication first: 5×2=105 \times 2 = 10 Then subtraction: 2010=1020 - 10 = 10. Since 103010 \neq 30, statement A is false.
  • Option B: 15÷3+415 \div 3 + 4 Division first: 15÷3=515 \div 3 = 5 Then addition: 5+4=95 + 4 = 9. Since 9=99 = 9, statement B is true.
  • Option C: 10+8÷210 + 8 \div 2 Division first: 8÷2=48 \div 2 = 4 Then addition: 10+4=1410 + 4 = 14. Since 14914 \neq 9, statement C is false.
  • Option D: 2×(5+3)2 \times (5 + 3) Parenthesis first: 5+3=85 + 3 = 8 Then multiplication: 2×8=162 \times 8 = 16. Since 161316 \neq 13, statement D is false. Therefore, only statement B is true.

Question 11

1 Mark

Simplify the following expression: 152×6+10÷515 - 2 \times 6 + 10 \div 5.

Options

Option A is correct

5

Option B

26

Option C

17

Option D

3

Explanation

According to the order of operations (BODMAS/PEMDAS):

  1. Multiplication and Division are performed before Addition and Subtraction. 2×6=122 \times 6 = 12 10÷5=210 \div 5 = 2 The expression becomes: 1512+215 - 12 + 2
  2. Perform Addition and Subtraction from left to right. 1512=315 - 12 = 3 3+2=53 + 2 = 5 Therefore, the correct answer is 5. Options 26, 17, and 3 are incorrect as they result from not following the correct order of operations.

Question 12

1 Mark

Evaluate the expression: 18÷(74)×2+518 \div (7 - 4) \times 2 + 5.

Options

Option A is correct

17

Option B

7

Option C

23

Option D

11

Explanation

Following the order of operations (BODMAS/PEMDAS):

  1. First, solve the operation inside the Brackets: 74=37 - 4 = 3 The expression becomes: 18÷3×2+518 \div 3 \times 2 + 5
  2. Next, perform Division and Multiplication from left to right: 18÷3=618 \div 3 = 6 The expression becomes: 6×2+56 \times 2 + 5 6×2=126 \times 2 = 12 The expression becomes: 12+512 + 5
  3. Finally, perform Addition: 12+5=1712 + 5 = 17 Therefore, the correct answer is 17. The other options are incorrect due to misapplication of BODMAS, such as performing addition before multiplication or division.

Question 13

1 Mark

What is the value of 5×(812)+20÷(4)-5 \times (8 - 12) + 20 \div (-4)?

Options

Option A is correct

15

Option B

-25

Option C

25

Option D

0

Explanation

Let's evaluate the expression step-by-step using BODMAS/PEMDAS, paying attention to integer rules:

  1. Solve the operation inside the Brackets first: 812=48 - 12 = -4 The expression becomes: 5×(4)+20÷(4)-5 \times (-4) + 20 \div (-4)
  2. Perform Multiplication and Division from left to right: 5×(4)=20 -5 \times (-4) = 20 (Product of two negative integers is positive) 20÷(4)=5 20 \div (-4) = -5 (Division of a positive by a negative integer is negative) The expression becomes: 20+(5)20 + (-5)
  3. Perform Addition: 20+(5)=205=1520 + (-5) = 20 - 5 = 15 Therefore, the value of the expression is 15. Incorrect options would arise from errors in integer arithmetic or order of operations.

Question 14

1 Mark

A shopkeeper earned Rs. 250 on Monday. On Tuesday, he spent Rs. 120. On Wednesday, he earned double the amount he spent on Tuesday. What is his net earning over these three days? Express this as an arithmetic expression and find its value.

Options

Option A is correct

Rs. 370

Option B

Rs. 290

Option C

Rs. 250

Option D

Rs. 320

Explanation

Let's break down the earnings and expenses:

  • Monday's earning: Rs. 250
  • Tuesday's spending: Rs. 120 (This is a negative earning or expense)
  • Wednesday's earning: Double the amount spent on Tuesday, which is 2×120=2402 \times 120 = 240 Rs. The arithmetic expression for the net earning is: 250120+2×120250 - 120 + 2 \times 120 Now, apply the order of operations (BODMAS/PEMDAS):
  1. Perform Multiplication: 2×120=2402 \times 120 = 240 The expression becomes: 250120+240250 - 120 + 240
  2. Perform Subtraction and Addition from left to right: 250120=130250 - 120 = 130 130+240=370130 + 240 = 370 Therefore, the net earning over these three days is Rs. 370. The other options are incorrect, likely due to errors in forming the expression or in the calculation steps.

Question 15

1 Mark

Which of the following expressions simplifies to 1010?

Options

Option A

205×2+420 - 5 \times 2 + 4

Option B is correct

(155)×2÷2(15 - 5) \times 2 \div 2

Option C

30÷(2+3)×130 \div (2 + 3) \times 1

Option D

40÷8+3×240 \div 8 + 3 \times 2

Explanation

We need to evaluate each expression using the order of operations (BODMAS/PEMDAS):

  1. Expression A: 205×2+420 - 5 \times 2 + 4 2010+420 - 10 + 4 (Multiplication first) 10+410 + 4 (Subtraction then Addition from left to right) =14= 14 (Not 10)

  2. Expression B: (155)×2÷2(15 - 5) \times 2 \div 2 10×2÷210 \times 2 \div 2 (Brackets first) 20÷220 \div 2 (Multiplication then Division from left to right) =10= 10 (This is 10)

  3. Expression C: 30÷(2+3)×130 \div (2 + 3) \times 1 30÷5×130 \div 5 \times 1 (Brackets first) 6×16 \times 1 (Division then Multiplication from left to right) =6= 6 (Not 10)

  4. Expression D: 40÷8+3×240 \div 8 + 3 \times 2 5+65 + 6 (Division and Multiplication first) =11= 11 (Not 10)

Therefore, only expression B simplifies to 10.

Question 16

1 Mark

Simplify the following arithmetic expression: 153×4+215 - 3 \times 4 + 2.

Options

Option A

2

Option B is correct

5

Option C

10

Option D

12

Explanation

According to the order of operations (BODMAS/PEMDAS), multiplication is performed before addition and subtraction. First, calculate 3×4=123 \times 4 = 12. The expression becomes 1512+215 - 12 + 2. Next, perform operations from left to right: 1512=315 - 12 = 3. Finally, 3+2=53 + 2 = 5. Thus, the correct answer is 5.

Question 17

1 Mark

Evaluate the expression: (5)×(68)+10(-5) \times (6 - 8) + 10.

Options

Option A

0

Option B

10

Option C is correct

20

Option D

-10

Explanation

First, solve the operation inside the parenthesis: 68=26 - 8 = -2. The expression becomes (5)×(2)+10(-5) \times (-2) + 10. Next, perform multiplication: (5)×(2)=10(-5) \times (-2) = 10. Finally, perform addition: 10+10=2010 + 10 = 20. Thus, the correct answer is 20.

Question 18

1 Mark

What is the value of the expression: 24÷4+5×3(102)24 \div 4 + 5 \times 3 - (10 - 2)?

Options

Option A is correct

13

Option B

16

Option C

20

Option D

23

Explanation

Follow the BODMAS/PEMDAS rule. First, solve the bracket: 102=810 - 2 = 8. The expression is now 24÷4+5×3824 \div 4 + 5 \times 3 - 8. Next, perform division and multiplication from left to right: 24÷4=624 \div 4 = 6 and 5×3=155 \times 3 = 15. The expression becomes 6+1586 + 15 - 8. Finally, perform addition and subtraction from left to right: 6+15=216 + 15 = 21, then 218=1321 - 8 = 13. So, the correct answer is 13.

Question 19

1 Mark

Which of the following represents the correct arithmetic expression for 'Subtract the product of 7 and 3 from the sum of 15 and 10'?

Options

Option A is correct

(15+10)(7×3)(15 + 10) - (7 \times 3)

Option B

(7×3)(15+10)(7 \times 3) - (15 + 10)

Option C

15+(107)×315 + (10 - 7) \times 3

Option D

15×107+315 \times 10 - 7 + 3

Explanation

The phrase 'sum of 15 and 10' translates to (15+10)(15 + 10). The phrase 'product of 7 and 3' translates to (7×3)(7 \times 3). The instruction 'Subtract A from B' means to write BAB - A. Therefore, 'Subtract the product of 7 and 3 from the sum of 15 and 10' translates to (15+10)(7×3)(15 + 10) - (7 \times 3). Option A correctly represents this.

Question 20

1 Mark

Simplify the complex arithmetic expression: [18{6+(10÷23)}]×4[18 - \{6 + (10 \div 2 - 3)\}] \times 4.

Options

Option A

20

Option B is correct

40

Option C

32

Option D

64

Explanation

Follow the BODMAS/PEMDAS rule for nested brackets, working from the innermost outwards:

  1. Innermost parenthesis: (10÷23)=(53)=2(10 \div 2 - 3) = (5 - 3) = 2.
  2. Curly braces: {6+2}=8\{6 + 2\} = 8.
  3. Square brackets: [188]=10[18 - 8] = 10.
  4. Finally, perform the multiplication: 10×4=4010 \times 4 = 40.
    Thus, the correct answer is 40.