Questions & Answers: "Differenciation"
Complete guide to "Differenciation" for Physics students. Below you will find important questions and model answers to help you prepare.
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We are building a dedicated quiz for this topic, but you can test your skills on a similar concept: Units and Measurement - NCERT Class 11 Practice Set 1.
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13 QuestionsFind the derivative of the function f(x) = 1/√x with respect to x at the point x = 4.
Options
-1/16
1/16
-1/4
1/4
Explanation
To find the derivative of f(x) = 1/√x, we first rewrite it in power form as f(x) = x^(-1/2). Applying the power rule (d/dx [x^n] = n*x^(n-1)), we get f'(x) = (-1/2) * x^(-1/2 - 1) = (-1/2) * x^(-3/2) = -1 / (2 * x^(3/2)). Now, substitute x = 4: f'(4) = -1 / (2 * 4^(3/2)). Since 4^(3/2) = (√4)^3 = 2^3 = 8, the derivative is -1 / (2 * 8) = -1/16. Option B is incorrect due to the sign; options C and D represent incorrect power rule applications.
If y = x / sin(x), what is the derivative dy/dx with respect to x?
Options
(sin(x) - x*cos(x)) / sin²(x)
(x*cos(x) - sin(x)) / sin²(x)
(sin(x) + x*cos(x)) / sin²(x)
1 / cos(x)
Explanation
We use the Quotient Rule: d/dx [u/v] = (vdu/dx - udv/dx) / v². Here, u = x and v = sin(x). Therefore, du/dx = 1 and dv/dx = cos(x). Substituting these into the formula: dy/dx = (sin(x) * 1 - x * cos(x)) / (sin(x))² = (sin(x) - x*cos(x)) / sin²(x). Option B reverses the order of the numerator terms (leading to a sign error), Option C incorrectly uses addition instead of subtraction, and Option D is a common mistake where students differentiate numerator and denominator independently (violating the quotient rule).
Using the chain rule, find the derivative of the function y = cos(x² + 5) with respect to x.
Options
2x * sin(x² + 5)
-2x * sin(x² + 5)
-sin(x² + 5)
-2x * cos(x² + 5)
Explanation
According to the chain rule, d/dx [f(g(x))] = f'(g(x)) * g'(x). Here, let f(u) = cos(u) where u = x² + 5. The derivative of the outer function f(u) is -sin(u), and the derivative of the inner function u = x² + 5 is 2x. Multiplying them together, we get dy/dx = -sin(x² + 5) * (2x) = -2x * sin(x² + 5). Option A misses the negative sign required for the derivative of cosine. Option C forgets to differentiate the inner function (the 2x term). Option D incorrectly keeps the cosine function instead of changing it to sine.
What is the derivative of f(x) = x * sin(x) with respect to x?
Options
cos(x)
sin(x) + x*cos(x)
sin(x) - x*cos(x)
x*cos(x)
Explanation
By applying the Product Rule [d/dx(uv) = u'v + uv'], where u = x and v = sin(x). Here u' = 1 and v' = cos(x). Thus, f'(x) = (1)sin(x) + (x)cos(x). Option A and D are incorrect because they only differentiated one part of the product. Option C is incorrect because it uses the wrong sign (subtraction instead of addition).
According to the first principle of derivatives, the derivative of a function f(x) at any point x in its domain is defined as:
Options
lim (h -> 0) [f(x+h) - f(x)] / h
lim (h -> 0) [f(x-h) - f(x)] / h
lim (h -> 0) [f(x+h) + f(x)] / h
lim (h -> infinity) [f(x+h) - f(x)] / h
Explanation
The derivative is the instantaneous rate of change, defined by the limit of the difference quotient as the increment 'h' approaches zero. Option A is the standard mathematical definition. Option B is incorrect because it uses f(x-h) - f(x) which would lead to the negative of the derivative unless the denominator was also -h. Option C is incorrect because the numerator must represent the change in y (difference), not the sum. Option D is incorrect because h must approach 0, not infinity, to find the slope at a specific point.
Find d/dx [sin(ax + b)], where a and b are constants.
Options
cos(ax + b)
a * cos(ax + b)
-a * cos(ax + b)
a * sin(ax + b)
Explanation
Using the Chain Rule, we differentiate the outer function sin(u) to get cos(u), and then multiply by the derivative of the inner function (ax + b), which is 'a'. Thus, result = a * cos(ax + b). Option A misses the inner derivative 'a'. Option C incorrectly adds a negative sign (derivative of sine is positive cosine). Option D fails to differentiate the sine function.
Find the derivative of f(x) = x^3 - 2x + 10 with respect to x.
Options
3x^2 - 2 + 10
3x^2 - 2
x^2 - 2
3x^2 - x
Explanation
Using the power rule d/dx(x^n) = nx^(n-1) and the rule that the derivative of a constant is 0: d/dx(x^3) = 3x^2, d/dx(-2x) = -2, and d/dx(10) = 0. Adding these gives 3x^2 - 2. Option A incorrectly kept the constant 10. Option C used the wrong coefficient for x^2. Option D incorrectly differentiated -2x.
Using the quotient rule, find the derivative of f(x) = (x + 1) / (x - 1).
Options
-2 / (x - 1)^2
2 / (x - 1)^2
1 / (x - 1)^2
-2 / (x + 1)^2
Explanation
The Quotient Rule states d/dx(u/v) = (u'v - uv') / v^2. Here u = x+1, v = x-1, u' = 1, v' = 1. So, f'(x) = [1*(x-1) - (x+1)*1] / (x-1)^2 = (x - 1 - x - 1) / (x-1)^2 = -2 / (x-1)^2. Option B has the wrong sign. Option C is missing the factor of 2. Option D uses the wrong denominator (x+1 instead of x-1).
Find the slope of the tangent to the curve y = x^2 at the point x = 3.
Options
3
9
6
2
Explanation
The slope of the tangent is the value of the derivative at that point. The derivative of y = x^2 is dy/dx = 2x. Evaluating at x = 3, we get 2(3) = 6. Option A is the x-value. Option B is the y-value (x^2). Option D is the derivative function's coefficient.
What is the derivative of f(x) = sec(x)?
Options
tan^2(x)
sec(x) * tan(x)
-sec(x) * tan(x)
sec^2(x)
Explanation
The derivative of sec(x) is a standard trigonometric derivative derived from 1/cos(x) using the quotient rule, resulting in sec(x)tan(x). Option A is incorrect as it's unrelated. Option C is incorrect because the derivative of sec(x) is positive (unlike csc(x)). Option D is the derivative of tan(x), not sec(x).
What is the derivative of f(x) = 1/x^2?
Options
-2 / x^3
2 / x^3
-1 / x
-2 / x
Explanation
f(x) = x^(-2). Applying the power rule: d/dx(x^-2) = -2 * x^(-2-1) = -2 * x^(-3) = -2 / x^3. Option B is missing the negative sign required by the power rule. Option C and D represent incorrect power subtractions.
Find the derivative of the constant function f(x) = sin(pi/3).
Options
cos(pi/3)
1/2
0
sqrt(3)/2
Explanation
Even though it looks like a trigonometric function, sin(pi/3) is a constant value (sqrt(3)/2). The derivative of any constant with respect to x is always 0. Option A is a common trap where students differentiate the sine part without realizing it's a constant. Options B and D are just values of trig functions, not derivatives.
If f(x) = sqrt(x), what is f'(x)?
Options
1 / (2 * sqrt(x))
2 * sqrt(x)
1 / sqrt(x)
-1 / (2 * sqrt(x))
Explanation
f(x) can be written as x^(1/2). Applying the power rule: d/dx(x^n) = n*x^(n-1), we get (1/2)*x^(1/2 - 1) = (1/2)x^(-1/2) = 1 / (2sqrt(x)). Option B is the reciprocal. Option C is missing the factor of 1/2. Option D incorrectly includes a negative sign.