Find the area of the region bounded by the curves y² = x and y = x.
Model Answer & Options
Source: Extra Practice1/6 sq. units
1/3 sq. units
1/2 sq. units
2/3 sq. units
Explanation
The curves intersect where x² = x, so x = 0 and x = 1. In the interval [0, 1], √x ≥ x. Area = ∫[0 to 1] (√x - x) dx = [2/3 x^(3/2) - x²/2] from 0 to 1 = 2/3 - 1/2 = 1/6. Option B is just the integral of √x, and option C is just the integral of x; option D is a common error in power rule application.
Try a Related Quiz
Test your skills on a similar concept: Units and Measurement - NCERT Class 11 Practice Set 1.
Explore the Full Topic
This is just one question from the topic "Area under curve".
View All QuestionsRelated Questions
- →
Determine the area bounded by the curve , the x-axis, and the vertical lines and .
- →
Find the area of the region bounded by the line , the x-axis, and the ordinates and .
- →
What is the total area under one complete arch of the sine curve, specifically from to ?
- →
Find the area of the circle x² + y² = a² using the method of integration.
- →
Find the area bounded by the parabola x² = 4y and the line y = 4.