The curves intersect where x² = x, so x = 0 and x = 1. In the interval [0, 1], √x ≥ x. Area = ∫[0 to 1] (√x - x) dx = [2/3 x^(3/2) - x²/2] from 0 to 1 = 2/3 - 1/2 = 1/6. Option B is just the integral of √x, and option C is just the integral of x; option D is a common error in power rule application.