Calculate the area of the region bounded by the curve y = x³, the x-axis, and the ordinates x = -1 and x = 1.
Model Answer & Options
Source: Extra Practice0 sq. units
1/4 sq. unit
1/2 sq. unit
1 sq. unit
Explanation
Area must be positive. From x = -1 to 0, x³ is negative, so we take the absolute value. Area = |∫[-1 to 0] x³ dx| + ∫[0 to 1] x³ dx = |[x⁴/4] from -1 to 0| + [x⁴/4] from 0 to 1 = |0 - 1/4| + (1/4 - 0) = 1/4 + 1/4 = 1/2. Option A is the result of a simple definite integral without taking absolute values for area. B and D are calculation errors.
Try a Related Quiz
Test your skills on a similar concept: Units and Measurement - NCERT Class 11 Practice Set 1.
Explore the Full Topic
This is just one question from the topic "Area under curve".
View All QuestionsRelated Questions
- →
Determine the area bounded by the curve , the x-axis, and the vertical lines and .
- →
Find the area of the region bounded by the line , the x-axis, and the ordinates and .
- →
What is the total area under one complete arch of the sine curve, specifically from to ?
- →
Find the area of the circle x² + y² = a² using the method of integration.
- →
Find the area bounded by the parabola x² = 4y and the line y = 4.